IGCSE Mathematics 0580 · Topic 6.2

IGCSE Mathematics: Trigonometry Practice Questions

Right-angled trigonometry links an angle to two sides of a triangle through sine, cosine and tangent. Label the sides opposite, adjacent and hypotenuse relative to the angle you are using, then choose the ratio that contains the two sides you know or want.

Cambridge IGCSE Mathematics (0580) · Topic 6.2: Trigonometry

Topic 6 of Cambridge IGCSE Mathematics 0580 is one of the most reliable sources of marks on Papers 2 and 4, provided you label the triangle before you calculate. This page covers right-angled trigonometry, which applies only to triangles containing a 90 degree angle. Non-right-angled triangles need the sine and cosine rules, which are a separate topic.

What you need to know for Trigonometry

IGCSE Mathematics Trigonometry questions and answers

4 exam-style questions written to the 0580 syllabus. Try each one on paper first, then open the worked answer to check your method against the marks.

Question 1[3 marks]

A right-angled triangle has a hypotenuse of 12 cm. One of the acute angles is 35 degrees. Calculate the length of the side opposite that angle. Give your answer to 3 significant figures.

Show the worked answer
Answer: 6.88 cm
  1. Label the sides. The hypotenuse is 12 cm and the unknown side is opposite the 35 degree angle.
  2. Opposite and hypotenuse means use sine: sin 35 = opposite / 12.
  3. Rearrange: opposite = 12 x sin 35.
  4. opposite = 12 x 0.5736 = 6.883, which is 6.88 cm to 3 significant figures.
How the marks are awarded. 1 mark for selecting sine and writing sin 35 = x / 12. 1 mark for correct rearrangement to x = 12 sin 35. 1 mark for 6.88 with the unit.
Where students lose the mark. Leaving the calculator in radian mode. If the answer comes out as roughly -5.6, the mode is wrong.
Question 2[3 marks]

In a right-angled triangle the side opposite angle A is 7.0 cm and the side adjacent to angle A is 9.0 cm. Calculate angle A to 1 decimal place.

Show the worked answer
Answer: 37.9 degrees
  1. Opposite and adjacent are known, so use tangent: tan A = opposite / adjacent.
  2. tan A = 7.0 / 9.0 = 0.7778.
  3. Take the inverse: A = tan-1(0.7778).
  4. A = 37.87 degrees, which is 37.9 degrees to 1 decimal place.
How the marks are awarded. 1 mark for choosing tangent and writing tan A = 7 / 9. 1 mark for using the inverse tangent. 1 mark for 37.9 degrees.
Where students lose the mark. Dividing 9 by 7. Tangent is opposite over adjacent, in that order. Reversing it gives 52.1 degrees, which is the other acute angle.
Question 3[4 marks]

A ladder of length 5.0 m rests against a vertical wall. The foot of the ladder is 1.4 m from the base of the wall. Calculate the angle between the ladder and the ground, and the height the ladder reaches up the wall. Give both answers to 2 significant figures.

Show the worked answer
Answer: The angle is 74 degrees and the height is 4.8 m.
  1. The ladder is the hypotenuse, 5.0 m. The distance along the ground, 1.4 m, is adjacent to the angle at the ground.
  2. Adjacent and hypotenuse means cosine: cos A = 1.4 / 5.0 = 0.28, so A = cos-1(0.28) = 73.74 degrees, which is 74 degrees to 2 significant figures.
  3. For the height, use Pythagoras: height2 = 5.02 - 1.42 = 25 - 1.96 = 23.04.
  4. height = square root of 23.04 = 4.80 m, which is 4.8 m to 2 significant figures.
How the marks are awarded. 1 mark for using cosine with 1.4 and 5.0. 1 mark for 74 degrees. 1 mark for a correct method for the height, using Pythagoras or sine. 1 mark for 4.8 m.
Where students lose the mark. Using the rounded angle to calculate the height. Rounding at an intermediate step can shift the final answer. Keep the unrounded value in your calculator, or use Pythagoras instead.
Question 4[4 marks]

A surveyor stands 40 m from the base of a tower on level ground. Her eyes are 1.6 m above the ground and the angle of elevation of the top of the tower from her eyes is 28 degrees. Calculate the height of the tower to 3 significant figures.

Show the worked answer
Answer: 22.9 m
  1. The angle of elevation is measured from the horizontal line at eye level, so the triangle has an adjacent side of 40 m.
  2. Opposite and adjacent means tangent: tan 28 = h / 40, where h is the height above eye level.
  3. h = 40 x tan 28 = 40 x 0.5317 = 21.27 m.
  4. Add the height of her eyes: total height = 21.27 + 1.6 = 22.87, which is 22.9 m to 3 significant figures.
How the marks are awarded. 1 mark for using tangent with the 40 m adjacent side. 1 mark for h = 40 tan 28. 1 mark for 21.3 m above eye level. 1 mark for adding 1.6 m to give 22.9 m.
Where students lose the mark. Forgetting to add the eye height. Angles of elevation are measured from the observer's eye, so any height below the eye must be added at the end.

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Trigonometry FAQs

What does SOHCAHTOA mean?

It is a memory aid for the three trigonometric ratios in a right-angled triangle. SOH means sine equals opposite over hypotenuse. CAH means cosine equals adjacent over hypotenuse. TOA means tangent equals opposite over adjacent. Label the triangle first, then pick the ratio containing the two sides you know or want.

How do I find an angle rather than a side?

Form the ratio using the two sides you know, then apply the inverse function on your calculator. For example, if the opposite side is 7 and the adjacent is 9, then tan A equals 7 divided by 9, and A equals the inverse tangent of that value, which is 37.9 degrees to one decimal place.

Can I use SOHCAHTOA on any triangle?

No. The three ratios only apply to right-angled triangles. For a triangle with no right angle you need the sine rule or the cosine rule, or you can split the triangle into two right-angled triangles by dropping a perpendicular.

What is the difference between angle of elevation and angle of depression?

Both are measured from the horizontal. The angle of elevation is the angle you look up through from the horizontal to see an object above you. The angle of depression is the angle you look down through from the horizontal to see an object below you. Always draw the horizontal line before marking the angle.

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Written to the published Cambridge IGCSE Mathematics (0580) syllabus. Check your school entry code and syllabus year, because Core and Extended candidates are assessed on different content. Last reviewed 2026-08-12.