IGCSE Mathematics 0580 · Topic 1.11

IGCSE Mathematics: Ratio and Proportion Practice Questions

To share a quantity in a given ratio, add the parts, divide the total by that number to find one part, then multiply. In direct proportion one quantity is a constant multiple of the other, and in inverse proportion their product is constant.

Cambridge IGCSE Mathematics (0580) · Topic 1.11: Ratio and Proportion

Topic 1.11 of Cambridge IGCSE Mathematics 0580 runs through the whole paper, appearing in geometry, statistics and problem solving as well as in number. Finding the value of one part, or the constant of proportionality, is the step that every question depends on. The questions below build that habit.

What you need to know for Ratio and Proportion

IGCSE Mathematics Ratio and Proportion questions and answers

4 exam-style questions written to the 0580 syllabus. Try each one on paper first, then open the worked answer to check your method against the marks.

Question 1[3 marks]

Share RM840 between three people in the ratio 3 : 4 : 5.

Show the worked answer
Answer: RM210, RM280 and RM350.
  1. Add the parts: 3 + 4 + 5 = 12 parts in total.
  2. Find the value of one part: RM840 divided by 12 = RM70.
  3. Multiply each share: 3 x 70 = RM210, 4 x 70 = RM280, and 5 x 70 = RM350.
  4. Check: 210 + 280 + 350 = RM840, which matches the original amount.
How the marks are awarded. 1 mark for a total of 12 parts. 1 mark for one part being RM70. 1 mark for all three shares correct.
Where students lose the mark. Dividing RM840 by 3 because there are three people. The division must be by the total number of parts, not the number of shares.
Question 2[4 marks]

y is directly proportional to the square of x. When x = 3, y = 18. Find the value of y when x = 5.

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Answer: y = 50
  1. Write the relationship as an equation: y = kx2.
  2. Substitute the known pair: 18 = k x 32 = 9k, so k = 2.
  3. The equation is therefore y = 2x2.
  4. Substitute x = 5: y = 2 x 25 = 50.
How the marks are awarded. 1 mark for writing y = kx2. 1 mark for finding k = 2. 1 mark for substituting x = 5. 1 mark for y = 50.
Where students lose the mark. Scaling y in the same ratio as x, giving 30. Because y depends on the square of x, multiplying x by five thirds multiplies y by twenty five ninths.
Question 3[4 marks]

The time t taken to complete a job is inversely proportional to the number of workers n. When 4 workers are used the job takes 6 hours. Find how long it takes with 3 workers.

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Answer: 8 hours
  1. Write the relationship: t = k divided by n.
  2. Substitute the known pair: 6 = k divided by 4, so k = 24.
  3. The equation is therefore t = 24 divided by n.
  4. Substitute n = 3: t = 24 divided by 3 = 8 hours. This is sensible, since fewer workers should take longer.
How the marks are awarded. 1 mark for writing t = k divided by n. 1 mark for k = 24. 1 mark for substituting n = 3. 1 mark for 8 hours.
Where students lose the mark. Treating it as direct proportion and giving 4.5 hours. Check the answer against common sense: fewer workers must mean more time.
Question 4[3 marks]

On a map with scale 1 : 25000, two towns are 6 cm apart. Calculate the actual distance between them in kilometres.

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Answer: 1.5 km
  1. A scale of 1 to 25000 means 1 cm on the map represents 25000 cm on the ground.
  2. 6 cm on the map therefore represents 6 x 25000 = 150000 cm.
  3. Convert to metres by dividing by 100: 150000 divided by 100 = 1500 m.
  4. Convert to kilometres by dividing by 1000: 1500 divided by 1000 = 1.5 km.
How the marks are awarded. 1 mark for multiplying by 25000 to get 150000 cm. 1 mark for converting to 1500 m. 1 mark for 1.5 km.
Where students lose the mark. Converting straight from centimetres to kilometres by dividing by 1000. There are 100000 centimetres in a kilometre, so the conversion needs two steps.

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Ratio and Proportion FAQs

How do I share an amount in a ratio?

Add the parts of the ratio to find the total number of parts, divide the amount by that total to find the value of one part, then multiply that value by each part of the ratio. Check by adding the shares back together to confirm they give the original amount.

What is the difference between direct and inverse proportion?

In direct proportion, y equals k multiplied by x, so as one quantity increases the other increases in the same ratio. In inverse proportion, y equals k divided by x, so as one increases the other decreases and their product stays constant.

How do I find the constant of proportionality?

Write the relationship as an equation with k, substitute the pair of values you are given, and solve for k. Then rewrite the complete equation with that value of k and use it to find the unknown quantity in the second part of the question.

How do I convert a map scale into real distances?

Multiply the map distance by the scale factor to get the real distance in the same unit. For a 1 to 25000 scale, 6 cm on the map represents 150000 cm on the ground. Divide by 100 for metres, then by 1000 for kilometres.

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Written to the published Cambridge IGCSE Mathematics (0580) syllabus. Check your school entry code and syllabus year, because Core and Extended candidates are assessed on different content. Last reviewed 2026-08-12.