IGCSE Mathematics 0580 · Topic 2.3

IGCSE Mathematics: Algebraic Fractions Practice Questions

An algebraic fraction is simplified by factorising the numerator and denominator and cancelling common brackets. Nothing can be cancelled across an addition or subtraction, only across a product.

Cambridge IGCSE Mathematics (0580) · Topic 2.3: Algebraic Fractions

Topic 2.3 of Cambridge IGCSE Mathematics 0580 is an Extended topic that punishes careless cancelling more than anything else on the paper. Factorise first, then cancel whole brackets. The questions below apply that rule to simplifying, adding and solving.

What you need to know for Algebraic Fractions

IGCSE Mathematics Algebraic Fractions questions and answers

4 exam-style questions written to the 0580 syllabus. Try each one on paper first, then open the worked answer to check your method against the marks.

Question 1[4 marks]

Simplify fully (x2 minus 9) divided by (x2 + 7x + 12).

Show the worked answer
Answer: (x minus 3) divided by (x + 4)
  1. Factorise the numerator. It is a difference of two squares: x2 minus 9 = (x + 3)(x minus 3).
  2. Factorise the denominator. Two numbers multiplying to 12 and adding to 7 are 3 and 4, so x2 + 7x + 12 = (x + 3)(x + 4).
  3. The fraction is now (x + 3)(x minus 3) over (x + 3)(x + 4).
  4. The bracket (x + 3) is a factor of both, so it cancels, leaving (x minus 3) divided by (x + 4).
How the marks are awarded. 1 mark for factorising the numerator. 1 mark for factorising the denominator. 1 mark for identifying the common bracket. 1 mark for the fully simplified answer.
Where students lose the mark. Cancelling the x2 terms or the 9 and the 12 before factorising. Cancelling is only valid once both parts are written as products.
Question 2[4 marks]

Write 3 divided by (x + 1) plus 2 divided by (x minus 2) as a single fraction in its simplest form.

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Answer: (5x minus 4) divided by (x + 1)(x minus 2)
  1. The common denominator is the product of the two denominators: (x + 1)(x minus 2).
  2. Adjust each numerator: the first becomes 3(x minus 2) and the second becomes 2(x + 1).
  3. Expand the numerators: 3x minus 6, and 2x + 2. Adding gives 5x minus 4.
  4. The single fraction is (5x minus 4) divided by (x + 1)(x minus 2). The numerator does not factorise, so this is fully simplified.
How the marks are awarded. 1 mark for the correct common denominator. 1 mark for both numerators adjusted correctly. 1 mark for expanding to 3x minus 6 and 2x + 2. 1 mark for the final single fraction.
Where students lose the mark. Adding the numerators and the denominators separately to give 5 over (2x minus 1). Fractions can only be added once the denominators match.
Question 3[3 marks]

Simplify (2x divided by 3) multiplied by (9 divided by 4x2).

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Answer: 3 divided by 2x
  1. Multiplying fractions means multiplying numerators and multiplying denominators.
  2. Numerator: 2x times 9 = 18x. Denominator: 3 times 4x2 = 12x2.
  3. The fraction is 18x over 12x2. Divide the numbers by their HCF of 6: 18 divided by 6 = 3 and 12 divided by 6 = 2.
  4. Cancel one x from top and bottom: the answer is 3 divided by 2x.
How the marks are awarded. 1 mark for multiplying the numerators and denominators. 1 mark for simplifying the numerical part. 1 mark for cancelling the x correctly to give 3 divided by 2x.
Where students lose the mark. Cancelling all the x terms and giving 3 over 2. There is one x on top and two on the bottom, so one x remains in the denominator.
Question 4[4 marks]

Solve (x + 1) divided by 2, minus (x minus 3) divided by 5, equals 2.

Show the worked answer
Answer: x = 3
  1. The lowest common denominator of 2 and 5 is 10. Multiply every term on both sides by 10 to clear the fractions.
  2. This gives 5(x + 1) minus 2(x minus 3) = 20.
  3. Expand carefully, applying the minus to both terms of the second bracket: 5x + 5 minus 2x + 6 = 20.
  4. Simplify to 3x + 11 = 20, so 3x = 9 and x = 3. Check by substituting back: (3 + 1) divided by 2 = 2, and (3 minus 3) divided by 5 = 0, and 2 minus 0 = 2.
How the marks are awarded. 1 mark for multiplying through by 10. 1 mark for 5(x + 1) minus 2(x minus 3) = 20. 1 mark for correct expansion including the sign change. 1 mark for x = 3.
Where students lose the mark. Expanding minus 2(x minus 3) as minus 2x minus 6. The minus sign must be applied to both terms, giving minus 2x plus 6.

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Algebraic Fractions FAQs

How do I simplify an algebraic fraction?

Factorise the numerator and the denominator completely, then cancel any bracket that appears in both. Cancelling before factorising is invalid, because you can only cancel factors, meaning parts that are multiplied, never terms that are added or subtracted.

Why can't I cancel the x squared terms in a fraction?

Cancelling is division, and dividing only works across a whole product. In an expression like x squared minus 9, the x squared is part of a subtraction, not a factor. Factorising it into (x + 3)(x minus 3) turns it into a product, at which point cancelling becomes valid.

How do I add two algebraic fractions?

Use the product of the denominators as the common denominator, multiply each numerator by the other denominator, then add the numerators over that common denominator. Expand and simplify the numerator, and check whether the result factorises and cancels.

How do I solve an equation containing algebraic fractions?

Multiply every term on both sides by the lowest common denominator, which clears all the fractions at once. Take care with signs when a bracketed numerator is being subtracted, then solve the resulting equation and substitute back to check.

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Written to the published Cambridge IGCSE Mathematics (0580) syllabus. Check your school entry code and syllabus year, because Core and Extended candidates are assessed on different content. Last reviewed 2026-08-12.